# Please solve the 9th question. Please do not provide any link. Q.9.  In the following figure, OP, OQ and OR are drawn perpendiculars to the sides BC, CA and AB respectively of triangle ABC. Prove that :$A{P}^{2}+B{P}^{2}+C{Q}^{2}=A{Q}^{2}+C{P}^{2}+B{R}^{2}$

Hi,
AP square will be AR square. So here is answer.

Here we will use pythagorus theorem

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