Please solve the following question fast....it's very urgent : (x+y-1) whole cube Share with your friends Share 0 Shruti Tyagi answered this Dear student, We know,x+y-13=x3+y-13+3xy-1x+y-1 --[using (a+b)3=a3+b3+3ab(a+b)]⇒x+y-13=x3+y3-1-3yy-1+3xy-1x+y-1 --[using (a-b)3=a3-b3-3ab(a-b)]⇒x+y-13=x3+y3-1-3yy-1+3xxy+y2-y-x-y+1⇒x+y-13=x3+y3-1-3y-1+3xxy+y2-2y-x+1⇒x+y-13=x3+y3-1+3y-1+3x2y+3xy2-6xy-3x2+3x⇒x+y-13=x3+y3-1+3y-3+3x2y+3xy2-6xy-3x2+3x⇒x+y-13=x3+y3+3x2y+3xy2-3x2+3x-6xy+3y-4 Regards 1 View Full Answer Yamini answered this I think it is solved with the formulae (a+b)3 0
