Please solve the following question: rn An ice cream cone consiting of a cone is surmounted by a hemisphere - Maths - Surface Areas and Volumes

Question

Please solve the following question:
rn
An ice cream cone consiting of a cone is surmounted by a
hemisphere The common radius of the hemisphere and the cone is 3 5
cm and the total height of the ice cream cone is 12 5 cm Calculate
the volume of ice cream in the cone

Ankush Jain · Accepted Answer

Given, radius of hemisphere = radius of cone = r = 3 5 cm Now, total height of ice cream cone = 12 5 cm Therefore, height of conical part = total height of ice cream cone - height of hemisphere â‡’ height of conical part = 12 5 cm - 3 5 cm = 9 cm Now, volume of ice-cream in the cone = volume of conical part + volume of hemisphere $= \frac{1}{3} π r^{2} h + \frac{2}{3} π r^{3} = \frac{1}{3} π r^{2} (h + 2 r) = \frac{1}{3} \times \frac{22}{7} \times (3 5)^{2} (9 + 2 \times 3 5) = \frac{1}{3} \times \frac{22}{7} \times (3 5)^{2} (9 + 7) = \frac{1}{3} \times \frac{22}{7} \times (3 5)^{2} \times 16 = 205 33 c m^{3}$

Please solve the following question:rnAn ice cream cone consiting of a cone is surmounted by a hemisphere. The common radius of the hemisphere and the cone is 3.5 cm and the total height of the ice cream cone is 12.5 cm. Calculate the volume of ice cream in the cone.

Please solve the following question:
rn
An ice cream cone consiting of a cone is surmounted by a hemisphere. The common radius of the hemisphere and the cone is 3.5 cm and the total height of the ice cream cone is 12.5 cm. Calculate the volume of ice cream in the cone.