Please solve the following questions please.
Without actual calculation, write the quotient when the sum of a 3-digit number abc and the number obtained by changing the order of digits cyclically i.e bca and cab is divided by
(i)111
(ii)(a+b+c)
(iii)37
(iv)3
The sum of digits of a 2-digit number is 11.If the number obtained by reversing the digits is 9 less than the original number, find the number.

Dear student, 

Regards 

  • 0
What are you looking for?