Please solve the

Dear Student,

The number of zeros in a factorial remains same for 5 consecutive numbers.
0!, 1!, 2!, 3!, 4! Have 0 zeroes
5!, 6!, 7!, 8!, 9! Have 1 zero

Similarly all number from one multiple of five to the other multiple of 5 have same number of zeros.

Therefore answer is (2) 5.  (80!, 81!, 82!, 83!, 84!)

Regards

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