Please solve these questions am unable to solve them
Dear student
Post multiple queries in a different thread.
The answer to question number 12 is below,
Let, F1 be the force applied to the smaller piston of cross-sectional area A1.
F1 = 50 kgf
A1 = πd2/4 = (3.14)(0.052)/4 = 0.0019625 m2
Let, F2 be the force exerted on the large piston of cross-sectional area A2.
A2 = πd2/4 = (3.14)(0.252)/4 = 0.0490625 m2
Now,
F1/A1 = F2/A2
=> F2 = (F1/A1)A2 = 1250 kgf
Regards