Please solve this.
Dear Student,
a/b+b/a=-1
So, a2+b2/ab=-1
a2+b2=-ab
a3-b3=(a-b)(a2+b2+ab)
As, a2+b2=-ab
a3-b3=(a-b)(ab-ab)
=(a+b) ×0
So, a3-b3=0
Regards
a/b+b/a=-1
So, a2+b2/ab=-1
a2+b2=-ab
a3-b3=(a-b)(a2+b2+ab)
As, a2+b2=-ab
a3-b3=(a-b)(ab-ab)
=(a+b) ×0
So, a3-b3=0
Regards