Please solve this experts pl Share with your friends Share 0 Rohit Babu answered this Dear Student,Given,mA=4mBAbase area=Bbase area ..............1The liquid thrust at the bottom of A is,FA=base area of A×pressure at the bottom of A⇒FA=Abase area×PASimilarly, the liquid thrust at the bottom of B is,FB=Bbase area×PBThe liquid filled in both vessels is the same.i.e;water and it is filled upto the same height h.Hence,PA=Pb=hρg⇒FAFB=Abase area×hρgBbase area×hρg=Abase areaBbase area=1 Using equation 1FA : FB =1 :1Regards. 0 View Full Answer