Please solve this for me tomorrow is my exam

Please solve this for me tomorrow is my exam 16. In a regular pentagon ABCDE prove that AC = BE 17. In a regular hexagon ABCDEF, prove that LBDF is equilateral.

 
Given- ABCDE is a regular pentagon
To show- AC = BE
In triangles ABC & ABE;
AB = AB ( common 0
angles ABC = BAE ( interior angle of a regular pentagon )
BC = AE ( side of a regular pentagon )
then, triangles ABC =~ ABE; by SAS
AC = BE ( by CPCT )
  • 1

Since it is a hexagon, therefore each interior angle will be of measure is 120°
Now ABF is isosceles.
Thus
Similarly we can show that

Thus

 .
Hence BDF is equilateral.

 
  • 1
What are you looking for?