Dear Student, 72cos70sin20+32cos55cosec35tan5tan25tan45tan85tan65=72cos90-20sin20+32cos90-35cosec35tan90-85tan90-65tan45tan85tan65=72sin20sin20+32sin35cosec35cot85cot65×1×tan85tan65=72sin20sin20+32sin35×1sin35cot85cot65×1×1cot85×1cot65=72+32= 5 Formula used , sin90-t= cos t , tan90-t= cot t , sinx= 1cosecxRegards

please solve this
please solve this (ii) Without using trigonometric tables, evaluate cos 700 3 cos 550 cosec 350 sin 200 2 tan 50 tan 250 tan 450 tan 850 tan 650 Ans. 51

Dear Student, \frac{7}{2} \frac{\cos 70}{\sin 20} + \frac{3}{2} \frac{\cos 55 cosec 35}{\tan 5 \tan 25 \tan 45 \tan 85 \tan 65} = \frac{7}{2} \frac{\cos (90 - 20)}{\sin 20} + \frac{3}{2} \frac{\cos (90 - 35) cosec 35}{\tan (90 - 85) \tan (90 - 65) \tan 45 \tan 85 \tan 65} = \frac{7}{2} \frac{\sin 20}{\sin 20} + \frac{3}{2} \frac{\sin 35 cosec 35}{\cot 85 \cot 65 \times 1 \times \tan 85 \tan 65} = \frac{7}{2} \frac{\sin 20}{\sin 20} + \frac{3}{2} \frac{\sin 35 \times \frac{1}{\sin 35}}{\cot 85 \cot 65 \times 1 \times \frac{1}{\cot 85} \times \frac{1}{\cot 65}} = \frac{7}{2} + \frac{3}{2} = 5 Formula used, \sin (90 - t) = \cos t, \tan (90 - t) = \cot t, sinx = \frac{1}{cosecx} Regards

View Full Answer

please solve this please solve this (ii) Without using trigonometric tables, evaluate cos 700 3 cos 550 cosec 350 sin 200 2 tan 50 tan 250 tan 450 tan 850 tan 650 Ans. 51

please solve this
please solve this (ii) Without using trigonometric tables, evaluate cos 700 3 cos 550 cosec 350 sin 200 2 tan 50 tan 250 tan 450 tan 850 tan 650 Ans. 51