Please solve this question??? ASAP!!!!!........ Share with your friends Share 0 Ankita Agarwal answered this Dear Student, We have G1and G2 as two geometric means between b and c i.e. b,G1,G2,c are in G.Pc = br4-1c = br3r = cb13G1 = br = bcb13 = b23c13G13 =b3cb = b2cG2 = br2 = bcb23 = b13c23G23 = b3c2b2 = bc2As A is AM of b and c, hence2A = b+c ....1Now, G1×G2 = b23c13× b13c23G1×G2 = bcNow, G13+G23G1G2 = b2c+bc2bcG13+G23G1G2 = bcb+cbcG13+G23G1G2 = b+cUsing equ.1,we getG13+G23G1G2 = 2A Regards 0 View Full Answer
