Please solve this question fast and please inform me

Dear Student
 

Speed of sound

c=\sqrt{\gamma R_* T_1}

Where,

\gamma = Adiabatic index

R_* = Mass-specific gas constant

T_1 = Temperature = 273.15+20 = 293.15 K

1.75c=\sqrt{\gamma R_* T_2}

Dividing the equations we get

\frac{1.75c}{c}=\frac{\sqrt{\gamma R_* T_2}}{\sqrt{\gamma R_* T_1}}\\\Rightarrow 1.75=\sqrt{\frac{T_2}{T_1}}\\\Rightarrow 1.75^2=\frac{T_2}{T_1}\\\Rightarrow 1.75^2=\frac{T_2}{293.15}\\\Rightarrow T_2=1.75^2\times 293.15\\\Rightarrow T_2=897.77\ K

The temperature of air would be 897.77 K

Regards

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