# Please solve this question with explanation of the solution..........

So,acc to the options 1, The possible value of principle quantum number(n) is 2 which is correct as value of n is 2 for be.

option 2 says that te possible value of azimuthal quantum number (l) is zero wic is correct as l=0 for s subshell.

option 3 says that the possible value of magnetic quantum number (m

_{l}) is 1, which is correct as for l = 0,there is only one possible orientation.

option 4 says that the species could be paramagnetic,which means if it has unpaired electrons then paramagnetic.Here,H and Be are diamagnetic and ti is paramagnetic so option 4 is also the correct statement

ββββAll the options are correct,so there is no incorrect option,there must be some mistake in these options.

Regards

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