Please...solve this question...

55. The measured voltage for the reaction with indicated concentration is 1.5V. Calculate E° Cr(s) + 3Ag⁺ (0.1M)→ Ag(s) + Cr⁺³ (0.3M)
(1) 1.35
(2) 1.4
(3) 1.65
(4) 1.55
 

Dear student,

Cr(s) + 3Ag⁺(aq) (0.1M) ---> Ag(s) + Cr³⁺ (aq)  (0.3M)

n= 1
E= 1.5

E=E^o - 0.059/n * logQ
E^o = 1.5 + 0.059 * log 0.3/(0.1)³
​​​​​​     = 1.5 + 0.059(2+ log3)
     = 1.5+0.14
E^o = 1.65 V (approx)          ​

(3) is the correct option

Regards