Please solve this question.

Dear student,

$E_{c e l l} = {E^{0}}_{c e l l} - \frac{0.0591}{2} \log (\frac{20}{2}) E_{c e l l} = 0 - \frac{0.0591}{2} \log 10 E_{c e l l} = - 0.03 V$

Regards

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