please solve this without using reduction formula

Dear student,cos7 x dx=cos6 x×cosx dx=(cos2 x)3×cos x dx   =(1-sin2 x)3×cos x dx   [cos2x=1-sin2 x]Let sin x=u   cosx dx=du=(1-u2)3 du=(1-u6+3u4-3u2) du    [(a-b)3=a3-b3+3ab2-3a2b]=du-u6 du+3u4 du-3u2 du=u-u77+3u55-3u33+c=-sin7 x7+3 sin5 x5-sin3 x+sin x+cRegards

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