Please solve this

13. In the adjoining figure, PL ⊥ QR; LQ = LS and LR > LQ.
Show that PR > PQ.
[Hint. ∆PLQ ≅ ∆PLS ⇒ ∠1 = ∠3. But, ∠3 > ∠2. ∴ ∠1 > ∠2.]

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