Dear student The excess pressure is given by ∆p∝1rso as time goes r increases and ∆p decreases so the plot will be like this

Please solve this,,

Dear student

T h e e x c e s s p r e s s u r e i s g i v e n b y ∆ p \propto \frac{1}{r} s o a s t i m e g o e s r i n c r e a s e s a n d ∆ p d e c r e a s e s s o t h e p l o t w i l l b e l i k e t h i s