If α, β and γ are roots of x3+px2+qx+r=0αβγ=-da=-rα-1βγβ-1αγγ-1αβ=αβγ-1βγαβγ-1αγαβγ-1αβ=αβγ-13αβγ2=-r-13-r2=-r+13r2

Please solve this

Please solve this If a, ß, Y are the roots of the equation x3 + px2 + qx + r = O, then find the value of

I f α, β a n d γ a r e r o o t s o f x^{3} + p x^{2} + q x + r = 0 α β γ = - \frac{d}{a} = - r (α - \frac{1}{β γ}) (β - \frac{1}{α γ}) (γ - \frac{1}{α β}) = (\frac{α β γ - 1}{β γ}) (\frac{α β γ - 1}{α γ}) (\frac{α β γ - 1}{α β}) = \frac{{(α β γ - 1)}^{3}}{{(α β γ)}^{2}} = \frac{{(- r - 1)}^{3}}{{(- r)}^{2}} = - \frac{{(r + 1)}^{3}}{r^{2}}