Please someone solve 4

Please someone solve 4 tCISE 22(A) 5. 3 12 4 Ans. c 4. From the following figure, find the values of : (i) sin B (ii) tan C (iii) sec2 B —.tan2B (iv) sin2C + cos2 C

Dear Student, 

In  ABD, AB2=AD2+BD2            using pythagoras theoremAB=AD2+BD2AB=32+42AB=5In ABCAC2=AB2+BC2               using pythagoras theoremAC=AB2+BC2AC=52+122AC=25+144AC=13 As AD=3 , therfore DC=AC-AD=13-3=10Hence DC=10Now, iinABC sinB=BCAC         =1213ii in BDCtan C=BDDC=410           =25iii inABCsec2B-tan2B=ACAB2-BCAB2                         =1352-1252                         =16925-14425                         =169-14425                         =2525                         =1iv in BDCsin2C+cos2C=BDBC2+DCBC2                          =4122+10122                          =262+562                          =436+2536                          =2936                        
Regards

  • 0
What are you looking for?