Please tell how to solve Q 5 Share with your friends Share 0 Atul Shaw answered this Dear student, Given, the medians of a triangle ABC intersect each other at point G . One of its medians is AD Using property when the medians of triangles intersect each other, it divides into ratio of 2:1. So, AG:GD= 2:1 or, GD=13 AD (1) Drawing a altitude CF from C to AD at F. So,Area of △ACD=12×base×altitude=12×AD×CF Area of △CGD=12×base×altitude=12×GD×CF =12×13×AD×CF ( GD=1 3AD, From 1) Taking the ratio of both the areas , Areaof△ACDAreaof△CGD=12×AD×CF12×13×AD×CF=3 or, Area of △ACD=3× Area of △CGDFor remaining queries , please start a new thread to get rapid assistance fromour experts.Regards 1 View Full Answer Soumil Pujakar answered this idk 0
