Please tell me this Q Q. Find the value of x if 2sinx 2 x = 3 cosx when x∈[0, 2π] Share with your friends Share 0 Mohammed Javed answered this Dear StudentGiven2 sin2x = 3 cos x=> 2 (1-cos2 x) - 3 cos x = 0=> 2 - 2cos2 x - 3 cos x = 0=> 2cos2 x + 3 cos x - 2 = 0=> 2cos2 x + 3 cos x - 2 + cos x -cos x= 0=> 2cos2 x + 4 cos x - cos x - 2 = 0=> 2 cos x (cos x +2) -1 (cos x +2) = 0=> (cos x + 2) (2 cos x -1) = 0Thereforecos x +2 = 0=> cos x = -2 ( Rejected)and2 cos x -1 = 0=> cos x = 12=> cos x = cos π3=> x = 2nπ± π3 , n ∈ ZRegards 0 View Full Answer
