Please tell the (c) bit
Solution : In the dihybrid cross involving Seed Shape and Seed Color, the F2 progeny will show the following Phenotypic Ratio -
9 (Round Yellow) : 3 (Round Green) : 3 (Wrinkled Yellow) : 1 (Wrinkled Green) = 16 progeny
The total number of F2 Progeny given in the question is 1600. We can simply replace this with the ratio given above. This turns out to be 900 (Round Yellow) : 300 (Round Green) : 300 (Wrinkled Yellow) : 100 (Wrinkled Green) = 1600 progeny
This means 900 seeds will be Round Yellow and 100 seeds will be Wrinkled Green seeds.
9 (Round Yellow) : 3 (Round Green) : 3 (Wrinkled Yellow) : 1 (Wrinkled Green) = 16 progeny
The total number of F2 Progeny given in the question is 1600. We can simply replace this with the ratio given above. This turns out to be 900 (Round Yellow) : 300 (Round Green) : 300 (Wrinkled Yellow) : 100 (Wrinkled Green) = 1600 progeny
This means 900 seeds will be Round Yellow and 100 seeds will be Wrinkled Green seeds.