pleaseansthisque.
THIN FILM OF SOAP SOLUTION (n = 1.4) lies on the top of a glass plate (n’ = 1.5). when visible light is incident almost normal to the plate , two adjacent reflection reflection maxima and minima are observed at two wavelengths 420 nm and 630 nm. The minimum thickness of the soap solution
1.420 nm
2.450 nm
3.630 nm
4.1260 nm

The minimum thickness of the soap solution must be of the order of minimum wavelength  of light on the soap solution. This is the basic condition of scattering to take place. The thickness of soap film minimum wave length of the wave to be scatteredor                       tsoap = λminimum. Therefore the Correct answer 1. 420nm.  

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