plllzz ans.40 no link pllzz
Given line is x - 2y - 7 = 0 .... (1)
Therefore, the slope of line (1) =
From P, draw PM perpendicular to the line (1) and produce it to a point P' suct that P'M = MP, then P' is the image of P in the line (1) and the line (1) is the right bisector of the segment PP'.
Let P' be (a,b).
Then slope of PP' = .
As (1) is perpendicular to PP', we get
Also, the mid-point of PP' is M.
Since (1) is the right bisector of segment PP', M lies on (1)
On solving (2) and (3), we get
a = 5 and b = -6
Hence, the image of P in the given line is P'(5,-6).