# plllzz ans.40 no link pllzz

**Given** line is x - 2y - 7 = 0 .... (1)

⇒

Therefore, the slope of line (1) =

From P, draw PM perpendicular to the line (1) and produce it to a point P' suct that P'M = MP, then P' is the image of P in the line (1) and the line (1) is the right bisector of the segment PP'.

Let P' be (a,b).

Then slope of PP' = .

As (1) is perpendicular to PP', we get

Also, the mid-point of PP' is M.

Since (1) is the right bisector of segment PP', M lies on (1)

On solving (2) and (3), we get

a = 5 and b = -6

Hence, the image of P in the given line is P'(5,-6).

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