plllzz ans.6th no link pllzz
Dear Student,
Burning of methane:
CH4 + 2O2→ CO2 + 2H2O
According to the reaction,
For complete burning 1 volume of methane, 2 volumes of Oxygen is required.
Hence, for burning 10 cm3 of methane, 20 cm3 of oxygen is required.
Since, air contains 20% of oxygen. So 100 cm3 of air will be required containing 20 cm3 of oxygen.
Burning of acetylene:
C2H2 +52 O2 → 2CO2 + H2O
According to the reaction,
For complete burning 1 volume of acetylene, 5/2 volumes of Oxygen is required.
Hence, for burning 10 cm3 of acetylene,52×10 = 25 cm3 of oxygen is required.
Since, air contains 20% of oxygen.
So, 20 cm3 oxygen is present in 100 cm3
Therefore, 25 cm3 oxygen will be present in10020×25 = 125 cm3
Hence, 125 cm3 of air will be required containing 25 cm3 of oxygen
Therefore, total amount of air = 100+125=225 cm3
Burning of methane:
CH4 + 2O2
According to the reaction,
For complete burning 1 volume of methane, 2 volumes of Oxygen is required.
Hence, for burning 10 cm3 of methane, 20 cm3 of oxygen is required.
Since, air contains 20% of oxygen. So 100 cm3 of air will be required containing 20 cm3 of oxygen.
Burning of acetylene:
C2H2 +
According to the reaction,
For complete burning 1 volume of acetylene, 5/2 volumes of Oxygen is required.
Hence, for burning 10 cm3 of acetylene,
Since, air contains 20% of oxygen.
So, 20 cm3 oxygen is present in 100 cm3
Therefore, 25 cm3 oxygen will be present in
Hence, 125 cm3 of air will be required containing 25 cm3 of oxygen
Therefore, total amount of air = 100+125=225 cm3