# plllzz ans.6th no link pllzz

**Burning of methane:**

CH

_{4}+ 2O

_{2}

_{2}+ 2H

_{2}O

According to the reaction,

For complete burning 1 volume of methane, 2 volumes of Oxygen is required.

Hence, for burning 10 cm

^{3}of methane, 20 cm

^{3}of oxygen is required.

Since, air contains 20% of oxygen. So 100 cm

^{3}of air will be required containing 20 cm

^{3}of oxygen.

**Burning of acetylene:**

C

_{2}H

_{2}+

_{2}

_{2}+ H

_{2}O

According to the reaction,

For complete burning 1 volume of acetylene, 5/2 volumes of Oxygen is required.

Hence, for burning 10 cm

^{3}of acetylene,

^{3}of oxygen is required.

Since, air contains 20% of oxygen.

So, 20 cm

^{3}oxygen is present in 100 cm

^{3}

Therefore, 25 cm

^{3}oxygen will be present in

Hence, 125 cm

^{3}of air will be required containing 25 cm

^{3}of oxygen

Therefore, total amount of air = 100+125=225 cm

^{3}

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