Plot the points A(9,6) and B(5,9) on the graph paper. These two points arethe vertices of a figure ABCD which is symmetrical about x = 5 and y = 6.Complete the figure on the graph. Write down the geometrical name ofthe figure. Share with your friends Share 1 priyanka saggu answered this At first we plot A9,6 and B5, 9 on the coordinate plane.From A draw a line parallel to x - axis that intersects y - axis at 0, 6Now this line represents y = 6.From B, draw a line parallel to y-axis, that intersects x-axis at 5,0.Now, this line will represent x = 5.Now, the above 2 lines will intersect at 5,6.Now, the distance between 9, 6 and 5, 6 is 4 units.So, mirror image of 9,6 on the line x = 5, will be 4 units towards the left of 5, 6.Hence the required point will be C1, 6.Now,the distance between 5, 9 and 5, 6 is 3 units.So, the mirror image of 5, 9 on the line y = 6, will be 3 units below the point 5, 6Hence the required point will be D5, 3 Now,AB = 5-92 + 9-62 = 16 + 9 = 5 unitsBC = 5 - 12 + 9 - 62 = 5 unitsCD = 5 - 12 + 3 - 62 = 5 unitsDA = 9-52 + 6-32 = 5 unitsNow,AC = 9-12 + 6 - 62 = 8 unitsBD = 5 - 52 + 9 - 32 = 6 unitsSince we have AB = BC = CD = ADand AC ≠ BDso, the given quadrilateral is a rhombus. 5 View Full Answer