Pls ans this question

Dear Student,

Given:
 ABC is an equilateral triangle. D is a point on the side BC such that BD = 1/3 BC

Proof:
In ΔABE and ΔACE
AB = AC  (Given)
AE = AE  (Common side)
∠AEB = ∠AEC  (90 °)
∴ ΔABE ≅ ΔACE   (RHS congruence criterion)
⇒ BE = EC  (c.p.c.t)

9AD2 = 7AB2

Regards

  • 0
What are you looking for?