Pls ans this question
Dear Student,
Given: ABC is an equilateral triangle. D is a point on the side BC such that BD = 1/3 BC
Proof:
In ΔABE and ΔACE
AB = AC (Given)
AE = AE (Common side)
∠AEB = ∠AEC (90 °)
∴ ΔABE ≅ ΔACE (RHS congruence criterion)
⇒ BE = EC (c.p.c.t)
Regards
Given: ABC is an equilateral triangle. D is a point on the side BC such that BD = 1/3 BC
Proof:
In ΔABE and ΔACE
AB = AC (Given)
AE = AE (Common side)
∠AEB = ∠AEC (90 °)
∴ ΔABE ≅ ΔACE (RHS congruence criterion)
⇒ BE = EC (c.p.c.t)
Regards