Pls ans this.....
Dear Student,
The dissociation reaction for Ca(OH)2 will be:
Ca(OH)2⇌Ca2++2OH−
Given : pH=9
Hence,we need to calculate pOH which is equal to:
pOH=14-pH
pOH=14−9=5
[OH−]=10−5M
Hence [Ca2+]=1/2*[10−5]
Thus Ksp=[Ca2+][OH−]2
=0.5*[10−5][10−5]2
Ksp=0.5×10−15
Regards