Pls ans this.....

Dear Student,
The dissociation reaction for Ca(OH)2 will be:
Ca(OH)2​⇌Ca2++2OH
Given : pH=9 
Hence,we need to calculate pOH which is equal to:
pOH=14-pH 
pOH=14−9=5
[OH]=10−5M
Hence [Ca2+]=1/2*[10−5]
Thus Ksp​=[Ca2+][OH]2
=0.5*[10−5][10−5​]2​​​​
Ksp=0.5×10−15

​​​​​Regards
​​​​​

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