Pls answer
6.    Find the value of x: 2^5x÷2^x=√(5&2^20 )

Dear Student,

$$\begin{gathered} Assuming that the question is \text{'}find the value of x: 2^{5x} ÷ 2^x = \sqrt[5]{2^{20}}\text{'} \\ Then the solution is :- \\ \frac{2^{5x}}{2^x} = \sqrt[5]{2^{20}} \\ \Rightarrow 2^{5x} \times 2^{-x} = {\left(2^{20}\right)}^{\frac{1}{5}} ......\left(as \frac{1}{a^b} = a^{-b} and \sqrt[b]{a} = a^{\frac{1}{b}}\right) \\ \Rightarrow 2^{5x - x} = 2^{20\times \frac{1}{5}} .......\left(as a^b\times a^c = a^{b+c} and {\left(a^b\right)}^c = a^{b\times c}\right) \\ \Rightarrow 2^{4x} = 2^4 \\ \sin ce base is same, therefore power also most be same \\ 4x = 4 \\ \Rightarrow x = \frac{4}{4} = 1 \end{gathered}$$

If this is not what you had in mind, then kindly post correct and clear query in separate thread for rapid assistance.

Regards,