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Dear Student
Given, 24metre wide river
Let the initial point of Leela be L
and, the initial point of Geeta be G
Distance between them = 24m
Leela moves 18m in the upward direction, so let her final point be M and,
Geeta moves 14m downward direction, so let her final point be H
Let N be the point opposite to M, and I be the point opposite to H
It is clear that MNHI is a rectangle with
MN = LG = IH = 24m
LM = GN = 18m
GH = LI = 14m
Now, for rectangle MNHI
MN = IH = 24m
MI = NH = ML + LI = NG + GH
or, MI = 18m + 14m
or, MI = NH = 32m
Now, the distance between their final position = distance between M and H
Since MH is the diagonal of the rectangle
Therefore MH2 = MI2 + IH2
Or, MH2 = 322 + 242
Or, MH2 = 1024 + 576 = 1600
Or, MH = √(1600)
MH = 40m
Therefore the distance between Leela and Geeta's final position is 40m
Regards
Given, 24metre wide river
Let the initial point of Leela be L
and, the initial point of Geeta be G
Distance between them = 24m
Leela moves 18m in the upward direction, so let her final point be M and,
Geeta moves 14m downward direction, so let her final point be H
Let N be the point opposite to M, and I be the point opposite to H
It is clear that MNHI is a rectangle with
MN = LG = IH = 24m
LM = GN = 18m
GH = LI = 14m
Now, for rectangle MNHI
MN = IH = 24m
MI = NH = ML + LI = NG + GH
or, MI = 18m + 14m
or, MI = NH = 32m
Now, the distance between their final position = distance between M and H
Since MH is the diagonal of the rectangle
Therefore MH2 = MI2 + IH2
Or, MH2 = 322 + 242
Or, MH2 = 1024 + 576 = 1600
Or, MH = √(1600)
MH = 40m
Therefore the distance between Leela and Geeta's final position is 40m
Regards