# Pls answer as soon as possible

Given, 24metre wide river

Let the initial point of Leela be L

and, the initial point of Geeta be G

Distance between them = 24m

Leela moves 18m in the upward direction, so let her final point be M and,

Geeta moves 14m downward direction, so let her final point be H

Let N be the point opposite to M, and I be the point opposite to H

It is clear that MNHI is a rectangle with

MN = LG = IH = 24m

LM = GN = 18m

GH = LI = 14m

Now, for rectangle MNHI

**MN = IH = 24m**

MI = NH = ML + LI = NG + GH

or, MI = 18m + 14m

or,

**MI = NH = 32m**

Now, the distance between their final position = distance between M and H

Since MH is the diagonal of the rectangle

Therefore

**MH**

^{2}= MI^{2 }+ IH^{2}

Or,

^{ }MH

^{2}= 32

^{2}+ 24

^{2}

Or, MH

^{2}= 1024 + 576 = 1600

Or, MH = √(1600)

MH = 40m

**Therefore the distance between Leela and Geeta's final position is 40m**

Regards

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