Dear student distance of nearest end from pole =2f-f2=3f21u+1v=1f2-3f+1v=-1f1v=23f-1f1v=-13fv=-3f 1distance of nearest end from pole =2f+f2=5f21u+1v=1f2-5f+1v=-1f1v=25f-1f1v=-35fv=-5f3 1Length of image isL=3f-5f3=4f3Regards

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d i s \tan c e o f n e a r e s t e n d f r o m p o l e = 2 f - \frac{f}{2} = \frac{3 f}{2} \frac{1}{u} + \frac{1}{v} = \frac{1}{f} \frac{2}{- 3 f} + \frac{1}{v} = \frac{- 1}{f} \frac{1}{v} = \frac{2}{3 f} - \frac{1}{f} \frac{1}{v} = \frac{- 1}{3 f} v = - 3 f . . . 1 d i s \tan c e o f n e a r e s t e n d f r o m p o l e = 2 f + \frac{f}{2} = \frac{5 f}{2} \frac{1}{u} + \frac{1}{v} = \frac{1}{f} \frac{2}{- 5 f} + \frac{1}{v} = \frac{- 1}{f} \frac{1}{v} = \frac{2}{5 f} - \frac{1}{f} \frac{1}{v} = \frac{- 3}{5 f} v = - \frac{5 f}{3} . . . 1 L e n g t h o f i m a g e i s L = 3 f - \frac{5 f}{3} = \frac{4 f}{3} R e g a r d s

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