Pls answer me fast

Dear student,

(i) THe volume of Gas B (HCl)  at STP = 22.4 L
the volume of NH3 = 67.2 L
therefore, the volume of any gas at STP of 1 mole = 22.4 L 
moles of NH3 = $\frac{given volume}{volume of 1 mole at STP}$ = 67.2 / 22.4 = 3
and moles of HCL = 22.4 / 22.4 = 1

(ii) reaction involved =   
$N{H}_{3 } + HCl \to N{H}_{4}Cl$
1 mole of NH3 reacts with 1 mole of HCl 
therefore, moles of NH3 given is 3 hence it it an excess reagent .
HCl is an limiting reagent hence formed the product.
it means 1 moles of HCl formed = 1 moles of $N{H}_{4}Cl$
according to mole concept = 1 mole of $N{H}_{4}Cl$ =  53 g

(iii) NH3 is an excess amount hence it is left behind after the completion of reaction.

(iv) $N{H}_3 + HCl \to N{H}_{4}Cl$

THe $N{H}_{4}Cl$ is released as a white fumes


Regards