Dear student, CuO (s) + H2 (g) ----> Cu (s) + H2O (l) Here CuO is getting reduced to Cu and H2 is getting oxidised to H2O Therefore CuO is oxidising agent and H2 is a reducing agent H2S + Cl2 -----> 2HCl + S Oxidizing Agent - Cl2 (as it oxidizes H2S to S) Reducing Agent - H2S (as it reduces Cl2 to HCl) Regards,

pls answer no 7(c)

Dear student,

CuO (s) + H₂ (g) ----> Cu (s) + H₂O (l)
Here CuO is getting reduced to Cu and H₂is getting oxidised to H₂O.
Therefore CuO is oxidising agent and H₂ is a reducing agent.

H₂S + Cl₂ -----> 2HCl + S
Oxidizing Agent - Cl₂ (as it oxidizes H₂S to S)
Reducing Agent - H₂S (as it reduces Cl₂ to HCl)

Regards,

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