pls answer only if u know!!

In ABC,    BC2 = AC2 - AB2   Pythagoras theoremBC = AC2 - AB2BC = 72 - x2 = 49 - x2Now, tan C = ABBC = x49 - x2cot A = ABBC = x49 - x2cos A = ABAC = x7sin C = ABAC = x7cos B = cos 90°  = 0Now,7-x tan C + 7 + x . cot A - 14 cos A + 21 sin C + 49+x2 . cos B=7-x×x49 - x2 + 7+x×x49 - x2 - 14× x7 + 21 × x7 + 49+x2 × 0=x7+x + x7-x - 2x + 3x + 0=x7-x  + x7+x + x49-x27+x . 7-x=x7-x  + x7+x + x49-x249-x2

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I also want this answer…plzz .…plzz
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Which ans do u want gupta
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