Pls answer q13 urgently...

D e a r s t u d e n t, l e t t h e w i d t h o f t h e c a r d b o a r d b e x t h e n l e n g t h = x + 6 a r e a = x (x + 6) A c c o r d i n g t o q u e s t i o n 27 < x (x + 6) < 40 s o l v i n g 27 < x (x + 6) x (x + 6) - 27 > 0 x^{2} + 6 x - 27 > 0 x^{2} + 9 x - 3 x - 27 > 0 x (x + 9) - 3 (x + 9) (x - 3) (x + 9) > 0 x > 3 o r x < - 9 \sin c e x c a n' t b e n e g a t i v e, t h e r e f o r e x < - 9 i s n o t a s o l u t i o n x > 3 s o l v i n g x (x + 6) < 40 x^{2} + 6 x - 40 < 0 x^{2} + 10 x - 4 x - 40 < 0 x (x + 10) - 4 (x + 10) < 0 (x - 4) (x + 10) < 0 x < 4 o r x > - 10 t h e r e f o r e x < 4 i s t h e s o l u t i o n w e h a v e 3 < x < 4 a s t h e p o s s i b l e w i d t h s o f r e a c \tan g l e . M i n i m i z in g o f w a s t a g e i n u t i l i z a t i o n o f r e s o u c e s l e a d s t o e f f i c i e n t u s a g e o f r e s o u r c e s w i t h o u t h a r m i n g t h e e n v i r o n m e n t a n d r e s o u r c e s . R e g a r d s

View Full Answer