Dear Student , Please find below the solution to the asked query : Let YZ plane divides the line segment joining the points 3,5,-7 and -2,1,8 in k : 1 By section formula ,Coordinates of point of intersection=-2k+3k+1 , k+5k+1 , 8k-7k+1On the YZ plane , x coordinate is zero -2k+3k+1=0-2k+3=0-2k=-3k=32Now,y- coordinate=32+532+1=135z-coordinate= 832-732+1=2So,Required point=0 , 135 , 2Correct option is A Hope this information will clear your doubts about the topic If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible Regards

Pls answer q18

Pls answer q18 17. The angle between the lines 2x —y = — 4: is (A) 00 (C) 450 18. The co-ordinates 3y (B) 300 (D) 900 e point in which the joining the points (3, 5 , - 7) and 2, 1, intersected by the plane YZ are given by 19. 13 5 13 2 The straight line 3 (A) Parallel to X-axis (B) Parallel to Y-axis (C) P to Z-axis (B) 0 13 5 is Perpendicular to Z-axis Angle between lines r = (i +2 j —

Dear Student ,

Please find below the solution to the asked query :

Let YZ plane divides the line segment joining the points (3, 5, - 7) and (- 2, 1, 8) in k : 1 . By section formula, Coordinates of point of intersection = (\frac{- 2 k + 3}{k + 1}, \frac{k + 5}{k + 1}, \frac{8 k - 7}{k + 1}) On the YZ plane, x coordinate is zero . \frac{- 2 k + 3}{k + 1} = 0 - 2 k + 3 = 0 - 2 k = - 3 k = \frac{3}{2} Now, y - coordinate = \frac{\frac{3}{2} + 5}{\frac{3}{2} + 1} = \frac{13}{5} z - coordinate = \frac{8 (\frac{3}{2}) - 7}{\frac{3}{2} + 1} = 2 So, Required point = (0, \frac{13}{5}, 2) Correct option is A .

Hope this information will clear your doubts about the topic .

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible .

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