Pls answer question no. (vi)

Dear Student

Total distance travelled by body is given by area under v-t graph of that body.
So here

Total distance covered = Area under AB graph +area under BC graph +Area under CD graph

A r e a u n d e r A B g r a p h = a r e a o f t r a i n g l e A E D + A r e a o f r e c \tan g l e O A E F A r e a u n d e r A B g r a p h = \frac{1}{2} \times 20 \times 3 + 20 \times 3 = 30 + 60 = 90 K M A r e a u n d e r B C g r a p h = A r e a o f r e c \tan g l e B F G C = 40 \times 3 = 120 K M A r e a u n d e r g r a p h C D = A r e a o f t r i a n g l e C G D = \frac{1}{2} \times 2 \times 40 = 40 K M T o t a l d i s \tan c e = 90 + 120 + 40 = 250 K m

Regards