Pls answer this query. This is the third time I am asking because i didn't get the answer the last time!!!Last time I got links which didn't have the accurate solution. This time pls send no links!!!? A body starts from rest with uniform acceleration of 1.2m/s^2. Find the distance covered in 3rd second. Share with your friends Share 0 Decoder_2 answered this Dear student,a=1.2m/s2u=0velocity after 2sec will be given byv=u+atv=0+1.2×2v=2.4m/snow t=1sec as the question is asking for the distance covered in third second onlythis 2.4 will become initial velocity for 3rd second S=ut+12at2S=2.4×1+0.5×1.2×1×1=3mRegards 1 View Full Answer Swapnil answered this distance =ut +1/2 at^2 from this formula you can find -1 Darshana R S answered this What is time here? 0