Pls answer this question wave optics Share with your friends Share 0 Rohit Babu answered this Dear Student,Given,d=0.2mm=0.2×10-3m, λ=5000A0=5000×10-10m, D=1.2m ,n=4The distance between fourth bright fringe and central maximum is,β=n λDd⇒β=4×5000×10-10×1.20.2×10-3=2.4×10-60.2×10-3=12×10-3m=12 mm, Option 2Regards. 2 View Full Answer
