# Pls do the sum Number 5 of Pythagoras theorem

Dear Student

Given hupotenuse is 20 and ratio of other two sides is 4 : 3
So, as per pythagoras theorem

h2 = p2 + b2    , 202 = (4x)2 + ( 3x)2
400 = 16x2 + 9x2
400 = 25x2
x2 = 400/ 25
x2  = 16
so   x  =  4
there for length of other two sides are 4$×$4 = 16 cm and  3$×$ 4 = 12 cm

Regards

• 1
It helped you

• 0
What are you looking for?