Pls do the sum Number 5 of Pythagoras theorem

Dear Student

Given hupotenuse is 20 and ratio of other two sides is 4 : 3
So, as per pythagoras theorem 
   
    h2 = p2 + b2    , 202 = (4x)2 + ( 3x)2
                             400 = 16x2 + 9x2
                              400 = 25x2
                                x2 = 400/ 25
                                x2  = 16
                         so   x  =  4 
there for length of other two sides are 4×4 = 16 cm and  3× 4 = 12 cm

Regards
   

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