Pls do the sum Number 5 of Pythagoras theorem

Dear Student

Given hupotenuse is 20 and ratio of other two sides is 4 : 3
So, as per pythagoras theorem 
   
    h² = ^p2 + b2    , 20² = (4x)² + ( 3x)²
                             400 = 16x² + 9x²
                              400 = 25x²
                                x² = 400/ 25
                                x²  = 16
                         so   x  =  4 
there for length of other two sides are 4$\times$4 = 16 cm and  3$\times$ 4 = 12 cm

Regards