pls do this question Share with your friends Share 0 Lovina Kansal answered this Dear Student, ∠XSQ = 90° And ∠XTQ = 90° QX = QX (This is the common side) Since QX bisects ∠Q the angle is equally split between the triangles) So, ∠XQS = ∠TQX So, △XTQ≅△XSQ XS = XT (According to CPCT) ...(1) Draw XW perpendicular to PR Similarly, we can prove that △XSR is congruent to △ XWR. So, XS = XW ... (2) So, from (1) and (2) now in △PXT and△PXW, ∠PTX = ∠PWX, PX=PX is common and XT = XW. BY R.H.S. △PXT≅△PXW, ∠XPT = ∠XPW and PX bisects the angle P. Regards. 0 View Full Answer Disha Adak answered this Nvbcbgjtjk -1
