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Solution:

$T h e v a p o r p r e s s u r e o f a i r o v e r w a t e r i s 10 a t m . T h e p a r t i a l p r e s s u r e o f n i t r o g e n = P_{N_{2}} = \frac{79 \times 10}{100} = 7.9 a t m = 7.9 \times 760 m m H g = 6004 m m H g T h e p a r t i a l p r e s s u r e o f o x y g e n = P_{O_{2}} = \frac{20 \times 10}{100} = 2 a t m = 1520 m m H g A c c o r d i n g t o H e n r y' s l a w, P_{N_{2}} = K_{H (N_{2})} \times X_{N_{2}} X_{N_{2}} = \frac{P_{N_{2}}}{K_{H (N_{2})}} = \frac{6004}{6.51 \times 10^{7}} = 9.22 \times 10^{- 5} X_{O_{2}} = \frac{P_{O_{2}}}{K_{H (O_{2})}} = \frac{1520}{3.30 \times 10^{7}} = 4.6 \times 10^{- 5}$

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