Pls give me answer no.6

Dear Student ,

Please find below the solution to the asked query :

Distance between Nafisa house and school = 2 \frac{3}{5} = \frac{13}{5} km Distance between school and Sujata' s house = \frac{3}{8} km Distance between Sujata' s house and Mary' s house = 1 \frac{1}{2} km = \frac{3}{2} Km To meet Sujata, Nafisa will have to go to Mary' s house since Sujata is at Mary' s house . So, Distance walked by Nasifa to meet Sujata = Distance between Nafisa house and school + Distance between school and Sujata' s house + Distance between Sujata' s house and Mary' s house = \frac{13}{5} + \frac{3}{8} + \frac{3}{2} = \frac{13 \times 8 + 3 \times 5 + 3 \times 20}{40} = \frac{104 + 15 + 60}{40} = \frac{179}{40} = 4 \frac{19}{40} Km Distance walked by Nasifa to meet Sujata is 4 \frac{19}{40} Kilometres .

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