Dear Student, if A can finish a work in 16 days then amount of work done by A in 1 day = 116If B finishes the work in 20 daysthen amount of work done by B in 1 day = 120Amount of work done by both A and B in 1 day = 116 + 120 = 980Amount of work done by both A and B in 8 day = 980 × 8 = 910Amount of work remaining = 1 - 910 = 110amount of work done by B in 1 day = 120amount of work done by B in 2 day = 120×2 = 110 which was thre remaining workSo, B needs 2 more days to finish the work â€‹â€‹â€‹â€‹â€‹â€‹Regards,

Pls help experts........

Dear Student,

i f A c a n f i n i s h a w o r k i n 16 d a y s ​ ​ ​ ​ ​ ​ ​ t h e n a m o u n t o f w o r k d o n e b y A i n 1 d a y = \frac{1}{16} I f B f i n i s h e s t h e w o r k i n 20 d a y s t h e n a m o u n t o f w o r k d o n e b y B i n 1 d a y = \frac{1}{20} A m o u n t o f w o r k d o n e b y b o t h A a n d B i n 1 d a y = \frac{1}{16} + \frac{1}{20} = \frac{9}{80} A m o u n t o f w o r k d o n e b y b o t h A a n d B i n 8 d a y = \frac{9}{80} \times 8 = \frac{9}{10} A m o u n t o f w o r k r e m a i n i n g = 1 - \frac{9}{10} = \frac{1}{10} a m o u n t o f w o r k d o n e b y B i n 1 d a y = \frac{1}{20} a m o u n t o f w o r k d o n e b y B i n 2 d a y = \frac{1}{20} \times 2 = \frac{1}{10} w h i c h w a s t h r e r e m a i n i n g w o r k S o, B n e e d s 2 m o r e d a y s t o f i n i s h t h e w o r k

Regards,

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