Pls help me out in this question ....I need help in ths

Dear student, NaCl → Na +(l) + Cl– Reaction At cathode: reduction of 2Na+ + e– → Na Reaction At anode: oxidation of 2Cl– → Cl2 + 2e– Q= n(e-)F = F. So, option 4 is correct: we have to give 1F charge to get 1 mole of Na. Regards,