pls hepl me with this question.
ARRANGE THE THREE CHARGES +q , -q, +q USING THE DISTANCE r , 2r, 2r TO GET A SYSTEM WITH ZERO POTENTIAL ENERGY
Hello everyone,
The potential energy will be zero for the following configuration of potential energy:
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Adding them we get potential energy of the system to be zero.
This is possible only when the +q & +q are at distance r and –q is at a distance 2r from both +q & +q.
Hence, the charges are placed at the vertices of an isosceles triangle as shown above.
Hope this helps you all,
Keep posting and have a nice day!