pls I need expert answer with step by step explanation

Dear Student,
The solution/s to your 1st query has/have been provided below:
1.
$$\begin{gathered} \frac{6p^2-36p+30}{p-1}=\frac{6(p^2-6p+5)}{p-1} \\ =\frac{6(p^2-5p-p+5)}{p-1} \\ =\frac{6\left\{p\right(p-5)-1(p-5\left)\right\}}{p-1} \\ =\frac{6(p-1)(p-5)}{p-1} \\ =6(p-5) \end{gathered}$$
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