Pls
Q. If ABCD is a square of side 12 cm, then what is the perimeter of the given figure?

Dear Student,

$$\begin{gathered} Perimeter of Square = 4\times side \\ Perimeter of Square ABCD= 4\times 12 = 48 cm \\ In the given figure, ADC and EDC are right angled triangles right-angled at D. \\ So, In △ADC, we have FD= 35 cm, AD= 12 cm and AF=? \\ By u\sin g pythagoras theorem, \\ A{F}^2=F{D}^2+A{D}^2 \\ AF= \sqrt{{\left(35\right)}^2+{\left(12\right)}^2} \\ AF= \sqrt{1225+144} \\ AF= 37 cm \\ Perimeter of triangle =Sum of all three sides \\ = 35+12+37 = 84 cm \\ Similarly, In △EDC, \\ E{C}^2=E{D}^2+D{C}^2 \\ {13}^2=E{D}^2+{12}^2 \\ 169=E{D}^2+144 \\ E{D}^2= 169-144 \\ ED= \sqrt{25}= 5 cm \\ Perimeter = 13+12+5 = 30 cm \\ \mathit{S}\mathit{o}\mathbf{,}\mathbf{ }\mathit{t}\mathit{o}\mathit{t}\mathit{a}\mathit{l}\mathbf{ }\mathit{P}\mathit{e}\mathit{r}\mathit{i}\mathit{m}\mathit{e}\mathit{t}\mathit{e}\mathit{r}\mathbf{=}\mathbf{ }\mathbf{48}\mathbf{+}\mathbf{84}\mathbf{+}\mathbf{30}\mathbf{ }\mathbf{=}\mathbf{ }\mathbf{162}\mathbf{ }\mathit{c}\mathit{m} \end{gathered}$$

Hope this information will clear your doubts about topic.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards