Pls solve 24th and 25th.Urgent

Q24. Simplify :

          36   × 216 1 2   × 25 3   × 5 5 2   × 6 - 3 × 25 - 2

Q25. Find the area of the figures:

                

Dear student,


24) 36×21612×253×552×6-3×25-2=6×6×6312×532×512×63×25252     ...[using a-m=1am]=6×632×532×512×63×52252         ...[using amn=amn]=6×632×532×512×63×5452=6×632×532×512×63×52                         ....[using aman=am-n   so 54-2=52 which gets cancelled by the Dn]=61+32+3×532+12+2=62+6+62×53+1+42=6142×584=67×52

25)

Area of region I (trapezium)=12×sum of sides×height=12×4+6×2=12×10×2=10 cm2In region IIAG=AD-DGAG=6-4AG=2cmArea of region II (triangle)=12×base ×htAG=12×4 ×2=2 cm2Area of region III (trapezium)=12×sum of sides×height=12×3+4×4=7×4=28 cm2Thus the area of entire fig=Area of region I+Area of region II+Area of region III=10 cm2+2 cm2+28 cm2=40 cm2

Regards

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