Pls solve 24th and 25th.Urgent Q24. Simplify : 36 × 216 1 2 × 25 3 × 5 5 2 × 6 - 3 × 25 - 2 Q25. Find the area of the figures: Share with your friends Share 1 Shruti Tyagi answered this Dear student, 24) 36×21612×253×552×6-3×25-2=6×6×6312×532×512×63×25252 ...[using a-m=1am]=6×632×532×512×63×52252 ...[using amn=amn]=6×632×532×512×63×5452=6×632×532×512×63×52 ....[using aman=am-n so 54-2=52 which gets cancelled by the Dn]=61+32+3×532+12+2=62+6+62×53+1+42=6142×584=67×52 25) Area of region I (trapezium)=12×sum of ∥sides×height=12×4+6×2=12×10×2=10 cm2In region IIAG=AD-DGAG=6-4AG=2cmArea of region II (triangle)=12×base ×htAG=12×4 ×2=2 cm2Area of region III (trapezium)=12×sum of ∥sides×height=12×3+4×4=7×4=28 cm2Thus the area of entire fig=Area of region I+Area of region II+Area of region III=10 cm2+2 cm2+28 cm2=40 cm2 Regards 1 View Full Answer Harsh Jain answered this Please find this answer 2 Harsh Jain answered this Please find this answer -1